[-4(-2)-8]+[-1-(-2)^3]+2(-2)^3
(8-8)+(-1+8)-64
7-64
57
Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank
boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time
boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet
The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates
(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x
1100x + x^2 = 1400x + 700000
x^2-300x -700000 = 0 quadratic formula yields x = 1000
One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m
Answer:
cant tell you the answer but i can tell you the person that messed up isn't that good at math
Step-by-step explanation:
Yes that’s it son welp ok
Answer:
-68
Step-by-step explanation:
X/17=-4
X=-68
So the answer is -68
