Mike bungee jump from a building with eight stories each story was 15 4/5 feet in height how tall is the building

Which equation shows the point slope form of the line that passes through (3,2) and has a slope of 1/3

olasank [31]

Answer:

y=-1/3x+4/3

Step-by-step explanation:

y-y1=m(x-x1) m=1/3 x1=3 y1=2

y-2=1/3(x-2)

y-2=-1/3x-2/3

y=-1/3x+4/3

7 0

3 years ago

Show that the dual of the exclusive-OR is equal to its complement.

Rzqust [24]

Solution:XOR: X+Y= XY’ + X’YDual of XOR:= (X +Y’)+(X’+Y)= XX’+XY +X’Y’ +YY’= XY + X’Y’ Complement of XOR (XNOR)= (X+Y)’= (XY’ + X’Y)’=(X’+Y)+(X +Y’)= XX’+ XY + X’Y’+YY’= XY + X’Y’
HOPE IT HELPS

7 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago

Joaquin has $1,300 in the bank and has investments worth $4,000. He also has $7,000 worth of credit card debt. What is Joaquin's

svetlana [45]

The answer to this question would be: -$1,700

In this question, we can separate the account into positive/debit and negative/credit value. The positive/debit value should be:

Joaquin has $1,300 in the bank
He has $4,000 worth of investment
Total positive value = $1300 + $4000= $5300

The negative value should be
$7,000 worth of credit card debt
Total positive value =$7000

Then the net worth should be: $5300 - $7000= -$1700

7 0

3 years ago

Solve for x. |4x - 5| > 7

trasher [3.6K]

Answer:

x>3

Step-by-step explanation:

|4x-5|>7

4x -5>7

4x >7+5

4x /4>12/4

x >3

solution set={4,5,6,---}

8 0

3 years ago

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