Answer:
$20 after the applied coupon
Step-by-step explanation:
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
22.046 lbs
Step-by-step explanation:
10kg is rounded to 22 pounds
Answer:
Step-by-step explanation:
The catch here is to break up sqrt(6) into 2 parts that use primes to define sqrt(6)
sqrt(3)* sqrt(6)
sqrt(6) can be broken up into sqrt(2*3) which equals sqrt(2)*sqrt(3)
sqrt(3)*sqrt(2)(sqrt(3)
sqrt(3)*sqrt(3)*sqrt(2)
3*sqrt(2)
