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Deffense [45]
3 years ago
13

Can anyone help me with my last two questions 13 points each

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
There is no question here
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Please help I'm really bad at logorithms.
Gnom [1K]
Sorry to hear that you already took the test. Here is how to do the problem:

2ˣ = 128               
Let's take log base 10 of both sides.
For simplicity, we'll just use the symbol log to mean log₁₀

log (2ˣ) = log (128)                   Remember that log(yˣ) = x log(y)
x log (2) = log (128)                 Divide both sides by log(2) to get x by itself
x = log (128) ÷ log (2)
3 0
3 years ago
Which of the following statements is true?
777dan777 [17]
The first one is correct.
There is a VERY simple way you can do this
Here is how.
It's called the "Butterfly Method" (IDK if anyone calls it that, but I do!)
So basically, you look at the numerator for one of your numbers, and the denominator of the other number, and you multiply them! So...
1/7, you would take the seven...
1/4, and multiply it by the one...
so 7×1
and you get seven!
Then you do...
1/7, take the one...
1/4, take the four...
so 1×4
and you get four!
Whichever one is bigger (or smaller, but only if you are trying to find out which fraction is smaller...) is your answer!
Hope this helped!!!!!!!!!!!!!!


3 0
3 years ago
How do you do this question?
katen-ka-za [31]

Answer:

0

Step-by-step explanation:

∫ sin²(x) cos(x) dx

If u = sin(x), then du = cos(x) dx.

∫ u² du

⅓ u³ + C

⅓ sin³(x) + C

Evaluate between x=0 and x=π.

⅓ sin³(π) − ⅓ sin³(0)

0

7 0
3 years ago
Read 2 more answers
List the sections of a business plan
Salsk061 [2.6K]

Answer:

Executive Summary. ...

Company Description. ...

Products and Services. ...

Market analysis: ...

Strategy and Implementation: ...

Organization and Management Team: ...

Financial plan and projections:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What property is shown here? (1 x 4) x 3 = 1 x (4 x 3)
irinina [24]
Answer:Associative Property of Multiplication
4 0
3 years ago
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