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Delvig [45]
3 years ago
7

A rock with a mass of 25 g is added to a graduated cylinder containing 45 mL of water. The water level rises to the 50mL mark. B

ased on this information, what is the density of the rock?
Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

We know the density of water is 1 gm/ml

Mass of rock = 25 g

Volume of rock = 5 ml

So the density of the rock is       25 g / 5 ml = 5 gm / ml

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Answer:

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Step-by-step explanation:

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Dmitry_Shevchenko [17]

Answer:

-292 1/2

Step-by-step explanation:

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2 years ago
50 POINTS
Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

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Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

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3 years ago
Solve the equation for x:<br> 2(8x – 16) = 48
mihalych1998 [28]
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3 0
2 years ago
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agasfer [191]

Given:

Consider the expression is

\dfrac{n^4}{n^{\frac{1}{2}}}

To find:

The simplified form of the given expression.

Solution:

We have,

\dfrac{n^4}{n^{\frac{1}{2}}}

Using the properties of exponents, we get

=n^{4-\frac{1}{2}}               \left[\because \dfrac{a^m}{a^n}=a^{m-n}\right]

=n^{\frac{8-1}{2}}

=n^{\frac{7}{2}}

Therefore, the simplified form of the given expression is n^{\frac{7}{2}}.

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