Answer:
Equation of line is:
Step-by-step explanation:
Let equation of line be y=mx+c
where m is the slope of line and c is the y-intercept
Line passes through (2, -1/2) and has a slope of 3
i.e. (x,y)=(2, -1/2) and m=3
i.e.
So, equation of line is:
Answer: the value for the associated test statistic is 1.2653
Step-by-step explanation:
Given that;
sample size one n₁ = 10
mean one x"₁ = 6.4
standard deviation one S₁ = 1.1
sample size two n₁ = 11
mean two x"₂ = 5.6
standard deviation one S₁ = 1.7
H₀ : μ₁ = μ₂
H₁ : μ₁ ≠ μ₂
Pooled Variance
sp = √( { [(n₁ - 1) × s₁² + (n₂ - 1) × s₂²] / (n₁ + n₂ - 2)} × (1/n₁ + 1/n₂))
we substitute
= √( { [(10 - 1) × (1.1)² + (11 - 1) × (1.7)²] / (10 + 11 - 2)} × (1/10 + 1/11))
= √( { [(9) × 1.21 + (10) × 2.89] / (19) } × (0.1909))
= √({[ 39.79 ] / 19} × (0.1909))
= √( 2.0942 × 0.1909)
= √( 0.39978 )
= 0.63228
Now Test Statistics will be;
t = ( x"₁ - x"₂) / sp
we substitute
t = ( 6.4 - 5.6) / 0.63228
t = 0.8 / 0.63228
t = 1.2653
Therefore the value for the associated test statistic is 1.2653
We plug in -10 as x and 6 as y. We get -30 - 60 - 24 = -90 - 24 = -114
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Hope this helps!
==jding713==
Answer:
The sample mean is 
and the sample median is 0.56
Step-by-step explanation:
The sample mean 
of observations 
is given by
Applying the above definition we get that
The sum of these 15 sample observations is
and the sample mean is
The sample median is obtained by first ordering the <em>n</em> observations from smallest to largest (with any repeated values included so that every sample observation appears in the ordered list). Then,
Sample median = The single middle value if n is odd = 
Sample median = The average of the two middle values if n is even = average of 
and 
Applying the above definition we get that
The data is already ordered and n = 15 so,
Sample median = 
= 0.56
Since perpendicular lines have their slopes as negative reciprocals, the negative reciprocal of the given slope (3) is -1/3. Therefore the a value is -1/3.
