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2 years ago

Pls Help i have no idea what im doing and this is overdue

Mathematics

2 answers:

kondaur [170]2 years ago

8 0

Answer:

A reflection of D over line l would simply look like a backwards D. Reflecting it again over the line m would make it look like it did originally, a normal D.

Step-by-step explanation:

gladu [14]2 years ago

8 0

D is translated at least 3 units behind L

D reflected across the line of L would look like the first image below
If you then reflect it across line M it would look like the second picture

Hope this helps!

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If I can type 120 words in 3 minutes, what is my rate per minute?

mario62 [17]

Answer:

40 words per minute

Step-by-step explanation:

$\frac{1}{y} :\frac{3}{120}$

y · 3 = 1 · 120

3y = 120

3y ÷ 3 = 120 ÷ 3

y = 40

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3 years ago

Read 2 more answers

Find the general solution of the nonhomogeneous differential equation x^2y''-2y=3(x^2) -1, (x>0).

Ira Lisetskai [31]

Answer:

G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

Step-by-step explanation:

We are given that non-homogeneous differential equation

$x^2y''-2y=3(x^2)-1$

It is Cauchy Euler equation

Substitute x=e^t x>0

Auxillary equation

$D'(D'-1)-2=0$

$D'^2-D'-2=0$

$(D'-2)(D'+1)=0$

$D'-2=0 \implies D'=2$

$D'+1=0\implies D'=-1$

Complementary solution

$y=C_1e^{-t}+C_2e^{2t}$

$y=C_1\frac{1}{x}+C_2x^2$

Particular solution

$y_p=\frac{3e^{2t}}{D'^2-D'-2}-\frac{e^{0t}}{D'^2-D'-2}$

$y_p=te^{2t}+\frac{1}{2}=x^2logx+\frac{1}{2}$

G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

Hence, general solution G.S= $C_1\frac{1}{x}+C_2x^2+x^2logx+\frac{1}{2}$

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4 years ago

What angle relationships can be used to prove that two lines intersected by a transversal are parallel?

GalinKa [24]

Answer:

You can look at the slope and plane.If the slope is the same, the y-intercept is different and both lines are found in the same plane; they are parrallel to each other. This is a way to be certain since there is proof behind it as a Parallel line definition.

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3 years ago

Need Help balancing the 3 questions on top

Scrat [10]

Answer:

4Na + 1O2 > 2Na2O

SF6 > 1S + 3F2

2FE2O3 > 4FE + 3O2

Step-by-step explanation:

1. Identify the Products and Reactants(always do O2 last)

2. determine how many atoms of each element are present on each side of the equation

3. Add Coefficients and never change the subscripts. If there's a coefficient in front of any compound, it is distributed to both elements.

4. find the total number of atoms on both sides of the equation and make sure they equal with each other

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4 years ago

The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s. At

musickatia [10]

Answer:

Volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

Step-by-step explanation:

Given: The radius of a right circular cone is increasing at a rate of $1.9$ in/s while its height is decreasing at a rate of $2.2$ in/s.

To find: The rate at which volume of the cone changing when the radius is $134$ in. and the height is $136$ in.

Solution:

We have,

$\frac{dr}{dt} =1.9 \:\text{in/s}$ , $\frac{dh}{dt}=-2.2\:\text{in/s}$ , $r=134 \:\text{in}$ , $h=136\:\text{in}$

Now, let $V$ be the volume of the cone.

So, $V=\frac{1}{3}\pi r^{2}h$

Differentiate with respect to $t$ .

$\frac{dv}{dt} =\frac{1}{3}\pi \left [ r^2\frac{dh}{dt}+h\left ( 2r \right )\frac{dr}{dt} \right ]$

Now, on substituting the values, we get

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ \left ( 134 \right )^2\left ( -2.2 \right )+\left ( 136\right )\left ( 2 \right )\left ( 134 \right )\left ( 1.9 \right ) \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ -39503.2+69251.2 \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ 29748 \right ]$

$\frac{dv}{dt} =9916\pi \frac{in^3}{s}$

Hence, the volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

6 0

3 years ago