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sattari [20]
3 years ago
9

II. The student then takes a 1.00 M stock

Chemistry
1 answer:
-BARSIC- [3]3 years ago
3 0

Answer:

0.244 M.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 1 M

Volume of stock solution (V₁) = 0.305 L

Volume of diluted solution (V₂) = 1.25 L

Molarity of diluted solution (M₂) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

1 × 0.305 = M₂ × 1.25

0.305 = M₂ × 1.25

Divide both side by 1.25

M₂ = 0.305 / 1.25

M₂ = 0.244 M

Thus, the molarity of the diluted solution is 0.244 M

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. A standard dry cell has an output voltage of A. 1.5 VDC. B. 1.1 VDC. C. 1.2 VDC. D. 2.0 VDC.
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A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the sol
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Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of Ba(OH)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.867g}{171g/mol}=0.00507mol         (1g=1000mg)

Now put all the given values in the formula of molality, we get

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pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pOH=-\log [OH^-]

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According to stoichiometry,

1 mole of Ba(OH)_2 gives 2 mole of OH^-

Thus 0.0298 moles of Ba(OH)_2 gives =\frac{2}{1}\times 0.0298=0.0596 moles of OH^-

Putting in the values:

pOH=-\log[0.0596]=2.82

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What does pressure measure
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