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3 years ago

II. The student then takes a 1.00 M stock

Chemistry

1 answer:

-BARSIC- [3]3 years ago

3 0

Answer:

0.244 M.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 1 M

Volume of stock solution (V₁) = 0.305 L

Volume of diluted solution (V₂) = 1.25 L

Molarity of diluted solution (M₂) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

1 × 0.305 = M₂ × 1.25

0.305 = M₂ × 1.25

Divide both side by 1.25

M₂ = 0.305 / 1.25

M₂ = 0.244 M

Thus, the molarity of the diluted solution is 0.244 M

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4 years ago

Read 2 more answers

For the reaction N2(g) + 2H2(g) → N2H4(l), if the percent yield for this reaction is 100.0%, what is the actual mass of hydrazin

barxatty [35]

Answer:

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Explanation:

The begining is in the reaction:

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