You must know the concentration of the acetic acid. Suppose the concentration is 0.1 M. The solution is as follows:
CH₃COOH → CH₃COO⁻ + H⁺
I 0.1 0 0
C -x +x +x
E 0.1 - x x x
Ka = (x)(x)/(0.1 - x)
1.8×10⁻⁵ = x²/(0.1 - x)
Solving for x,
x = 1.333×10⁻³ = H⁺
pH = -log[H⁺] = -log(1.333×10⁻³)
pH = 2.88
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
Once you identify the compound as Ionic<span>, </span>Molecular, or an Acid, follow the individual ... chemicalformulas<span>, write </span>whether<span> the compound is </span>ionic or molecular<span>, and ...</span>
Answer:
Volume of liquid = 28.7 mL
Explanation:
Given data;
Density of solid = 3.57 g/ml
Mass of solid = 19.5 g
Volume of water = 23.2 mL
Total volume when solid is dropped into graduated cylinder= ?
Solution:
Density = mass/ volume
v = m/d
v = 19.5 g/ 3.57 g/ml
v = 5.5 mL
Volume of liquid = volume of water + volume of solid
Volume of liquid = 23.2 mL + 5.5 mL
Volume of liquid = 28.7 mL
