Which linear function represents the line given by the point-slope equation y + 7 = (x + 6)?

Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o

Katyanochek1 [597]

<h2>Answer:</h2>

$\boxed{R_{4}=20\Omega}$

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current $I$ is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance of series combination and the four resistors as follows:

$R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}$

$R_{eq}$ is the total resistance $50\Omega$ . Moreover:

$R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega$

Therefore:

$50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}$

7 0

3 years ago

Find the derivative of sinx/1+cosx, using quotient rule

Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

$f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}$

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}$

Now we can simplify that:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}$

And we know that:

cos^2(x) + sin^2(x) = 1

then:

$f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}$

4 0

3 years ago

I'm confused can someone maybe help me? (Picture below)

Shalnov [3]

Answer:

hlo ji good evening ji please follow me

4 0

3 years ago

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

so

$z=\frac{x}{y}$

we have

$x=12\ cm$

$y=9\ cm$

substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

so

$z^{2}=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

$x=390*16/9=693.33\ cm^{2}$

4 0

2 years ago

What is the area of a circle with a radius of 35 inches<br> in2<br> (Use 3.14 for Pi.)

Amanda [17]

Answer: area= 3846.5 inch^2

Step-by-step explanation:

Area of circle = πr^2

Where r is the radius and pi is 3.14

So, we get..

3.14 x (35)^2

= 3.14 x 35 x 35

= 3.14 x 1225

= 3846.5 inch^ 2

6 0

3 years ago

Read 2 more answers