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Svetllana [295]

3 years ago

14

CAN SOMEONE HELP

2 answers:

rusak2 [61]3 years ago

6 0

The two triangles are similar triangles.
The smaller triangle has hypotenuse 6 and a horizontal leg of 4
The large triangle has hypotenuse 6+12=18 and a horizontal leg of x, where x is some number larger than 4

Because the triangles are similar, we can form the proportion below and solve for x
x/4 = 18/6
6*x = 4*18
6*x = 72
6*x/6 = 72/6
x = 12

Final Answer: 12

trasher [3.6K]3 years ago

5 0

The answer to this question is 12

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Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

The perimeter of pqrs is 84. Find the length of each side qr=3(rs)

kramer

Pq= 10.5, qr=31.5, rs=10.5, sp=31.5

3 0

3 years ago

Factor the quadratic expression 4x^2-8x+3

nataly862011 [7]

Answer: (2x-1) (2x-3)

Step-by-step explanation:

8 0

3 years ago

What is the anwser pls help

Bas_tet [7]

Answer:

b. 0.09

Step-by-step explanation:

0.09 is the only one smaller than 0.59

0.59>0.09

3 0

2 years ago

Read 2 more answers

Ksivusya [100]

Vertical compression would be 1/13.
so g(x)=(6/13)x + 2
but if that's not right and it's a stretch then it's
g(x)=78x+2

7 0

3 years ago

Read 2 more answers