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3 years ago

An animal shelter has 36 pets available for adoption. 1/4 of them are puppies. How many are puppies?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

3 0

The answer is 9

Explanation: 1/4 of 36= 9

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PLS HELP ME WITH THHESE I GIVE ALL YALL BRAINLZESS

Olegator [25]

Answer:

1. R

2. Match the year with the price. For example, 2006 should have a line directly on 15.

3. A (The first number on each row is the second number multiplied by 4)

4. C

5. A

MAKE SURE TO DOUBLE-CHECK JUST IN CASE!

7 0

3 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

4 years ago

If 28% of a sum is 100.80 what is the sum

Sveta_85 [38]

$360.00*.28= 100.80

Or do a portion 

28%/100%=100.8/x 

Then cross multiply 

10080=28x 

x=360

4 0

3 years ago

What is the slope of the line? -2/5 2/5 5/2 1/3

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

(0, 3) (5, 1)

(1-3)/(5-0) = -2/5 is the slope

6 0

4 years ago

Read 2 more answers

Help me please i do not know the answers

konstantin123 [22]

can you make the pic little more clear if you can :)

8 0

3 years ago