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harina [27]
3 years ago
7

Whats the answer to this please

Mathematics
1 answer:
anastassius [24]3 years ago
3 0
Y = 3x
so
if x = 5 then y = 15
if x = 10 then y = 30

so a = 10 and b = 15

answer is B. second choice
a = 10 and b = 15
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The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent
Assoli18 [71]

Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

7 0
3 years ago
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X = quarters
y = dimes

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3 years ago
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