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2 years ago

Qual é a diferença entre a população de Toledo e Umuarama?

Mathematics

1 answer:

Inessa05 [86]2 years ago

3 0

E preciso subtrair.

119207
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18491

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Please help !! Solve for x: -2 -2/3 -3/2 -3

Kryger [21]

Answer:

x = $\frac{3}{2}$

Step-by-step explanation:

Given 2 intersecting chords, then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

18x = 9 × 3 = 27 ( divide both sides by 18 )

x = $\frac{27}{18}$ = $\frac{3}{2}$

8 0

2 years ago

What is a polynomial function in standard form with zeros 1,2,-3and -1

ki77a [65]

Answer:

p(x)= (x+1)(x+2)(x-3)(x-1)

then,multiplying two two terms

(x^2 +2x+x+2)(x^2-x-3x+3)

(x^2+3x+2)(x^2-4x+3)

x^4- 4x^3+3x^2 +3x^3-12x^2+9x+2x^2-8x+6)

x^4-x^3-7x^2+x+6

7 0

3 years ago

Which function has two x intercepts one at (0,0) and one at (4,0)

marta [7]

Answer:

f(y) = y(y - 4).

Step-by-step explanation:

The function has two x-intercepts of the function are (0,0) and (4,0).

X-intercept means that the y-value will be zero.

Therefore, the function f(y) has two roots, one at y = 0 and another at y = 4.

Hence, the function x = f(y) has two factors (y - 0) and (y - 4)

So, the function is f(y) = (y - 0)(y - 4) = y(y - 4). (Answer)

8 0

3 years ago

Willis bought a gallon of paint.He painted a wall that is 9 feet high and 10 feet wide.Then he used he rest of the paint to pain

Otrada [13]

First you need to find the surface area of the wall that was painted, and then add the additional area in the hallway that was painted.

The wall that was painted was 9 feet by 10 feet, or 90 square feet. 90 square feet plus the additional 46 square feet in the hallway is 136 square feet, which is the total area that the paint covered.

Therefore the solution is 136 square feet.

7 0

2 years ago

Read 2 more answers

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

3 years ago