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2 years ago

1. Find the distance between each pair of points. Round your answer to

Mathematics

1 answer:

zlopas [31]2 years ago

7 0

Step-by-step explanation:

$\sqrt{(3 - ( - 4))^{2} + ( - 7 - 6)^{2} } \\ = \sqrt{(3 + 4)^{2} + {( - 13)}^{2} } \\ = \sqrt{ 49 + 169} \\ = \sqrt{218} \\ = 14.7648$

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Simplify 5x^2+43x-18=0

GalinKa [24]

Answer:

-9, 2/5

Step-by-step explanation:

$5x^2 +43x-18=0 \\ \\ (5x-2)(x+9)=0 \\ \\ x=-9, \frac{2}{5}$

8 0

1 year ago

What is the greatest common factor for 20,and 45x

nadya68 [22]

<span>20: 1,2,4,5,10,20
45: 1,3,5, 9, 15,45
so five is the greatest common factor of 20 and 45x</span>

4 0

3 years ago

Can someone help me find AC

Kryger [21]

Answer:

1.4

Step-by-step explanation:

simply use your theta the top angle of 35 degrees hit sin on your calculator set up the proportion

x .700

2 1

cross multiply to end up with 1.4

4 0

2 years ago

A fast-food company is interested in knowing the probability of whether a customer viewed an advertisement for their new special

lord [1]

Answer:

45% probability that a randomly selected customer saw the advertisement on the internet or on television

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a customer saw the advertisement on the internet.

B is the probability that a customer saw the advertisement on television.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a customer saw the advertisement on the internet but not on television and $A \cap B$ is the probability that the customers saw the advertisement in both the internet and on television.

By the same logic, we have that:

$B = b + (A \cap B)$

12% saw it on both the internet and on television.

This means that $A \cap B = 0.12$

20% saw it on television

This means that $B = 0.2$

37% of customers saw the advertisement on the internet

This means that $A = 0.37$

What is the probability that a randomly selected customer saw the advertisement on the internet or on television

$A \cup B = A + B - (A \cap B) = 0.37 + 0.2 - 0.12 = 0.45$

45% probability that a randomly selected customer saw the advertisement on the internet or on television

6 0

2 years ago

Rewrite as a simplified fraction 2.67 repeating

Morgarella [4.7K]

265/99, is what I think but I’m not sure

5 0

2 years ago