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Mathematics

2 answers:

Scorpion4ik [409]3 years ago

8 0

10/10 i could never

enyata [817]3 years ago

5 0

Answer:

I would rate it a solid 9 because its nice and neat

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2(6-x) =3 step by step !

r-ruslan [8.4K]

Answer:

5½ = x

Step-by-step explanation:

$2(6 - x) = 3 \\ \\ 6 - x = 1 \frac{1}{2}$

-6 - 6

______________

-x = -5½

x = 5½

I am joyous to assist you anytime.

4 0

3 years ago

Read 2 more answers

Suppose a punter kicks a football so that the upward component of its velocity is 80 feet per second. If the ball is 3 feet off

Alexxandr [17]

So hmm check the picture below

$\bf \qquad \textit{initial velocity}\\\\ h = -16t^2+v_ot+h_o \qquad \text{in feet}\\
\\
v_o=\textit{initial velocity of the object}\\
h_o=\textit{initial height of the object}\\
h=\textit{height of the object at "t" seconds}\\\\
-----------------------------\\\\
h(t)=3+80t-16t^2\iff h(t)=-16t^2+80t+3$

a)

well, clearly is 80 ft/s

b)

when t = 1? well 80(1)

c)

in the picture, x-axis is the time and y-axis is the height
so, it reaches its maximum at the vertex, after "x" seconds

$\bf \begin{array}{lcccll}
h(t)=&-16t^2&+80t&+3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so it reached the vertex after $\bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds$

d)

the maximum height of the ball is $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet$