Answer:
12/13
Step-by-step explanation:
A probability is the number of desired outcomes over the total number of outcomes.
Assuming that this is a standard deck of playing cards, there will be 52 cards, and there will be 4 "4" cards.
First, find the number of desired outcomes, and put it over the total number of outcomes.
Out of the total number of outcomes (52), there are 4 outcomes that are not wanted, hence the equation is:
52 - 4 = 48
So out of the 52 possible outcomes, 48 are desired. Set up the fraction and
simplify:
48/52
/4 /4
= 12/13
Lets call x the amount of 18% solution and y the amount of 40% solution, and write as equations the info of the problem:
18x + 40y = 10(20)
x + y = 10
lets multiply the second equation by -18 and add to the first:
18x + 40y = 200
-18x -<span> 18y = -180
</span>----------------------
0 + 22y = 20
y = 20/22 = 10/11
and substitute in the original equation:
x <span>+ y = 10
</span>x = 10 - y
x = 10 - 10/11
x = 110/11 - 10/11
x = 100/11
so they have to use 100/11 liters of 18% solution and 10/11 liters of 40% solution
<h3>
Answer: 35 inches</h3>
Each side of the pentagon is multiplied by 5/3 to get the length of each new side, so the perimeter is multiplied by 5/3 to get the new perimeter.
New perimeter = (scale factor)*(old perimeter)
New perimeter = (5/3)*(old perimeter)
New Perimeter = (5/3)*(21)
New Perimeter = (5/3)*(21/1)
New Perimeter = (5*21)/(3*1)
New Perimeter = 105/3
New Perimeter = 35 inches
Answer:
2(3(8))+2(8)=64
Step-by-step explanation:
Here, w represents the width of the rectangle,
∵ length of the rectangle is 3 times the width of the rectangle,
So, length = 3w,
Since, the perimeter of a rectangle, P = 2(length + width)
= 2(w + 3w)
= 2w + 2(3w)
If P = 64 feet,
⇒ 2w +2(3w) = 64
⇒ 2w + 6w = 64
⇒ 8w = 64
⇒ w = 8
Verification :
P = 2(8) + 2((3(8)) = 16 + 48 = 64 feet
Hence, the first step that should be taken to verify that the width of the rectangle is 8 is 2(3(8))+2(8)=64
Note : a solution obtain from an equation is verified by substituting the value in the equation.