The answer to your question is 2/11
Answer:
6/8 and 9/12
Step-by-step explanation:
You can find any by multiplying numerator and denominator by any given number. The number multiplied has to be the same for the top and the bottom
1. Number is 2
3/4 * 2/2 = 6/8 (3*2 = 6 and 4*2 = 8)
2. Number is 3
3/4*3/3 = 9/12 (3*3 = 9 and 3*4 = 12)
Answer:
For this case we can conclude that with 98% of confidence the true proportion of Drosophila in a population would be between 0.34 and 0.38.
But that doesn't means that we have 98% of PROBABILITY that the true proportion would be between 0.34 and 0.38, because we are constructing a confidence interval with sample data and we can't analyze this using probability.
Then the best answer is:
2. False
Step-by-step explanation:
For this case we have a confidence interval for the proportion of Drosophila in a population with mutation Adh-F to be given by:
For this case we can conclude that with 98% of confidence the true proportion of Drosophila in a population would be between 0.34 and 0.38.
But that doesn't means that we have 98% of PROBABILITY that the true proportion would be between 0.34 and 0.38, because we are constructing a confidence interval with sample data and we can't analyze this using probability.
Then the best answer is:
2. False
Answer:
8.2+/-0.25
= ( 7.95, 8.45) years
the 95% confidence interval (a,b) = (7.95, 8.45) years
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 8.2 years
Standard deviation r = 1.1 years
Number of samples n = 75
Confidence interval = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
8.2+/-1.96(1.1/√75)
8.2+/-1.96(0.127017059221)
8.2+/-0.248953436074
8.2+/-0.25
= ( 7.95, 8.45)
Therefore the 95% confidence interval (a,b) = (7.95, 8.45) years
Answer:
Step-by-step explanation:
Explanation:
The
average rate of change
of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the
secant line
connecting the 2 points.
To calculate the average rate of change between the 2 points use.
∣
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
g
(
b
)
−
g
(
a
)
b
−
a
a
a
∣
∣
∣
−−−−−−−−−−−−−−−
g
(
6
)
=
6
2
−
6
+
3
=
33
and
g
(
4
)
=
4
2
−
4
+
3
=
15
Thus the average rate of change between (4 ,15) and (6 ,33) is
33
−
15
6
−
4
=
18
2
=
9
This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9
