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erik [133]
3 years ago
12

Does anyone know the answer to these questions???

Mathematics
2 answers:
Alika [10]3 years ago
4 0

Answer:

  • 2 is -1/3
  • 3 is y ≥-13
  • I don't know number 4 sorry :(
  • Step-by-step explanation:

Dmitriy789 [7]3 years ago
3 0

Answer:b b c

Step-by-step explanation:

fjsiwjensksnsfhnsnazkxisj done

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The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
Write and solve a real-world word problem in which there are 3 tables for every 8 chairs.
alekssr [168]
That means there are 24 chairs. What you would do is multiply 8 by 3 which gives you 24. 
4 0
3 years ago
Evaluate b²c¹ for b=8 c=-4
AVprozaik [17]

Answer:

The answer is -256.

Step-by-step explanation:

You have to substitute the value of b and c into the expression :

{b}^{2}  {c}^{1}

Let b = 8,

Let c = -4,

{8}^{2}  \times  { - 4}^{1}

= 64 \times  - 4

=  - 256

8 0
3 years ago
63 first-graders and 21 other students attended a school assembly. What percentage of the
boyakko [2]

Answer:

75%

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the additive version of the complex number -8+3i
Lana71 [14]

Answer:

8-3i

Step-by-step explanation:

The complex additive inverse is the number we need to add so that we get zero.  It is the negative of the number.

a + bi is –(a + bi) = –a – bi.

a+bi + (-a+-bi) = a-a + bi-bi = 0

The complex additive invers of -8+3i is

-(-8+3i)

Distribute the negative

8 -3i

6 0
3 years ago
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