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3 years ago

9

Savannah sets her watch 10.03 seconds behind and it falls behind another 1.09 seconds everyday. How many days has it been since

Savannah last set her watch if the watch is 36.19 seconds behind?

2 answers:

Pani-rosa [81]3 years ago

8 0

Answer:

1 and 1/2 days

Step-by-step explanation:

ITHINK ITS HELP GOOD LUCK

BabaBlast [244]3 years ago

8 0

Answer:

$|22 \sqrt[11]{26} | 2 \geqslant 13 \leqslant = 1$

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What is another way to write 54?

never [62]

Answer:

None of the above.

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3 years ago

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An insurance company has a merit rating system for customers who have not filed a claim in the previous year. For each year that

Valentin [98]

Answer:

B. Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

Step-by-step explanation:

The options above are examples of recurrence relations where the present state Fₙ₊₁ is dependent on the previous state Fₙ.

For each year that a customer does not file a claim, their rate is reduced by 15%

Fₙ-(15% of Fₙ)= Fₙ-0.15Fₙ

A credit of $5 is also awarded, therefore:

Fₙ - 0.15Fₙ + $5

Therefore If a customer did not file a claim in the nth year, the customer's rate in the (n + 1)th year as a function of their rate in the nth year is given by:

Fₙ₊₁ = Fₙ - 0.15Fₙ + 5

4 0

3 years ago

Which expression is equivalent to 3 sqrt 27x^18

shusha [124]

Assuming your original expression was 3√(27x¹⁸), the answer is 9x⁹√(3).

We split up the radicand into perfect squares. Once we do, we take out the things that were squared:
$3\sqrt{27x^{18}} = 3\sqrt{3\times3\times3x^2x^2x^2x^2x^2x^2x^2x^2x^2x^2} = 3*3*xxxxxxxxx\sqrt{3}
$
$=9x^9\sqrt{3}$

6 0

3 years ago

Write a linear inequality to represent the information given. The total fees for the high school play are $220. Tickets to the p

Vladimir [108]

Answer:

$5x + $7y ≥ $220

Step-by-step explanation:

Total Fees = $220

Total income is $5x plus $7y

Income = $5x + $7y

We want the total income to be equal to, or greater than, $220:

$5x + $7y ≥ $220

5 0

2 years ago

Help please, i don't understand it!!!!

velikii [3]

$V=\dfrac{4}{3}\pi r^3\ \ \ |\cdot\dfrac{3}{4}\\\\\pi r^3=\dfrac{3V}{4}\ \ \ \ |:\pi\\\\r^3=\dfrac{3V}{4\pi}\ \ \ |:r\\\\r^2=\dfrac{3V}{4\pi r^2}$

Substitute to S.A.

$S.A.=4\pi r^2=4\pi\cdot\dfrac{3V}{4\pi r^2}=\dfrac{3V}{r}$

$\dfrac{S.A.}{V}=\dfrac{4\pi r^2}{\frac{4}{3}\pi r^3}=\dfrac{3}{r}$

$\dfrac{S.A.}{V}=1\to\dfrac{3}{r}=1\to r=3$

Answer: B

6 0

4 years ago