a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.
Subtracting each equation from the one after gives
Subtracting the first of these equations from the second gives
Using the next previous equation, we can find m.
Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.
Answer:
-1
Step-by-step explanation:
2 × (-1²) + 1 = 2 × (-1) + 1 = -2 + 1 = -1
Step-by-step explanation:
taking that blank as x
5/2 -x = 1/3
the x will go to the right hand side of the equation which then would make it positive ( making x the subject) and 1/3 will come to the left hand side of the equation becoming -1/3
so the equation will become 5/2-1/3=x
solving the fraction then gives 13/6 or 2.17 as the value of x
Answer:
It goes up one number counting each time
Step-by-step explanation:
3 4 5 2 one cap
5 8 13 two cap
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