Answer:
Sue must use 3 hotdogs and 4 half-cup serving of baked beans.
Step-by-step explanation:
Let the number of hot dogs be represented by h
Let the number of baked beans be represented by b
Hot dogs have 13 grams of fat and 145 calories each
Baked beans have 8 grams of fat and 330 calories per half cup serving
Sue wants to plan a meal with 71 grams of fat and 1755 calories.
Grams of Fat from Hotdog + grams of fat from baked beans=71
13h+8b=71....(I)
Similarly,
Calories from hot dog + Calories from baked beans=1755
145h+330b=1755....(II)
We then solve Equations (I) and (II) simultaneously.
13h+8b=71....(I)
145h+330b=1755....(II)
Multiply equation 1 by 145 and equation 2 by 13
1885h+1160b=10295
1885h+4290b=22815
Subtracting
-3130b=-12520
b=4
Substitute b=4 into (I)
13h+(8X4)=71
13h=71-32
13h=39
h=3
Sue must use 3 hotdogs and 4 half-cup serving of baked beans.
Answer:
5.99999996667
Step-by-step explanation:
Answer:
The correct answer is A. 167 milliliters of 7% solution and 333 milliliters of 4% solution and here is how:
If x is the number of milliliters of the 7% saline solution and y is the number of milliliters of the 4% saline solution then add up to 500 milliliters total, so x + y = 500.
and if we do
x + y = 500
x = 500 - y
0.07x + 0.04y = 25 (substitute 500 - y for x)
0.07(500 - y) + 0.04y = 25
35 - 0.07y + 0.04y = 25
-0.03y + 35 = 25
-0.03y = -10
y = 333.333...
y = about 333
x = 500 - y = 500 - 333 = 167
Then you know why the answer is A.
Step-by-step explanation:
