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Maslowich
2 years ago
8

The area of a rectangle is 320 in^2. The ratio of the length to the width is 5:4. Find the length and the width.

Mathematics
1 answer:
Leviafan [203]2 years ago
8 0

Answer:

  • length: 20 in
  • width: 16 in

Step-by-step explanation:

Let w represent the width of the rectangle. Then the length is 5/4w, and the area is ...

  A = LW

  320 in² = (5/4w)(w)

  256 in² = w² . . . . . . . . . multiply by 4/5

  16 in = w . . . . . . . . . . . . take the square root

  5/4w = 5/4(16 in) = 20 in . . . . the length

The length of the rectangle is 20 inches; its width is 16 inches.

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Which property is illustrated by this problem?
Mnenie [13.5K]

This would be communicative property cause when solve the left side then the right they both come up to being 30=30.

8 0
3 years ago
Mary practiced violin for 2 hours and her brother practiced trombone t times as long or 8 hours. Write and solve an equation to
Bond [772]

Answer:

Mary's brother practiced 4 times as long.

Step-by-step explanation:

Mary practiced violin for 2 hours.

Her brother practiced trombone t times as long or 8 hours.

t times of 2 hours = 2t hours

But, 2t = 8

Divide both sides by 2.

t = 4

Hence, Mary's brother practiced 4 times as long as Mary.

4 0
3 years ago
Can someone help me please
Nesterboy [21]
1. The triangle is Isosceles and acute A (since there are two equal sides and the angles are less than 90)
2. Right triangle E (since there is a right angle)
3. The triangle is obtuse scalene T (since there are no equal sides and one angle is greater than 90)
4. Right isosceles O
5. Acute equilateral N
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8 0
3 years ago
In 7 hours, operators at a call center make 4,732 telemarketing calls
aalyn [17]

Based on the information given the number of calls did the center make per hour is 676 per hour.

Using this formula

Number of call per hour=Number of  telemarketing calls/Number of hours

Where:

Number of  telemarketing calls=4,732

Number of hours=7 hours

Let plug in the formula

Number of call per hour=4,732/7 hours

Number of call per hour=676 per hours

Inconclusion the number of calls did the center make per hour is 676 per hour.

Learn more about time here:brainly.com/question/23560939

8 0
3 years ago
Prove that: (Sec A- cosec A)(1+ tan A+cot A) = tan A× sec A - cot A × cosec A
mash [69]

Answer:

Step-by-step explanation:

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA

we take the LHS so here goes,

(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA\\(\frac{1}{cosA} -\frac{1}{sinA})(1+\frac{sinA}{cosA}+\frac{cosA}{sinA})\\\\(\frac{sinA-cosA}{sinAcosA})(\frac{sinAcosA+sin^2A+cos^2A}{sinAcosA})\\

since , sin^2A+cos^2A=1

the identity becomes,

(\frac{sinA-cosA}{sinAcosA})(\frac{1+sinAcosA}{sinAcosA})\\\\(\frac{sinA+sin^2AcosA-cosA-cos^2AsinA}{sin^2Acos^2A})\\\\

now, we know,

sin^2A=1-cos^2A and cos^2A=1-sin^2A

the identity becomes,

(\frac{sinA+(1-cos^2A)cosA-cosA-(1-sin^2A)sinA}{sin^2Acos^2A} )\\\\

(\frac{sinA+cosA-cos^3A-cosA-sinA+sin^3A}{sin^2Acos^2A})

sin A and cos A cancel out it becomes zero

\frac{sin^3A-cos^3A}{sin^2Acos^2A} \\\\

Splitting the denominator the identity becomes

\frac{sin^3A}{sin^2Acos^2A}-\frac{cos^3A}{sin^2Acos^2A}  \\\\\frac{sinA}{cos^2A} - \frac{cosA}{sin^2A} \\\\\frac{sinA}{cosA}(\frac{1}{cosA})-\frac{cosA}{sinA}(\frac{1}{sinA})\\\\

Hence,

tanAsecA-cotAcosecA

3 0
3 years ago
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