Answer:
The Magnitude of charge = q = 15.47 micro coulomb
Step-by-step explanation:
The attractive force between two points q and - 2 q = F = 2.2 Newton
The separation between two charges = 1.4 meters
Now from Coulomb's law = F = 
where k= 
So , 2.2 = ( 
So , q ² = (
)
For charge magnitude
I.e q ² = 
so, q = 
q = 15.47 \times 10^{-6} c
Or, q = 15.47 micro coulomb
Hence the Magnitude of charge = q = 15.47 micro coulomb Answer
They are equal because
1 yd=3ft
25 yds= x feet
x= 25*3
feet=75
Answer:
12 5 dollar bills
20 50 dollar bills
Step-by-step explanation:
Let x = number of five dollar bills
Let y = number of fifty dollar bills
We have a total of 32 bills
x+y = 32
The total amount is 1060
5x+50y = 1060
We have 2 equations and 2 unknowns
x+y = 32
5x+50y = 1060
Multiply the first equation by -5 so we can eliminate x
-5x -5y = -5*32
-5x -5y =-160
Add this to the second equation
5x+50y = 1060
-5x -5y =-160
------------------------
45 y = 900
Divide each side by 45
45y/45 = 900/45
y = 20
There are 20 50 dollar bills
x+y = 32
x+20 = 32
Subtract 20 from each side
x+20-20 = 32-20
x = 12
There are 12 5 dollar bills
Answer:
8
Step-by-step explanation:
20-7=13
13^1.50=8.66666666667
Round up with 8 or 9
20+4x. Multiply the 4 by the 5 and bring the sign over. Do same for x
