There is a 0.833 chance that she pulls a golden earring
Answer:
B , D , A ,C
Step-by-step explanation:
PEMDAS
The answer is P= 80/19
hope this helps
Recall that for

, i.e. a random variable

following a binomial distribution over

trials and with probability parameter

,

So you have




The expected value of

is simply

, while the standard deviation is

. In this case, they are

and

, respectively.