The height is 5 m. The area of a trapezoid is (b1+b2/2)h
Answer:
Width = 12 in
Length = 16 in
Step-by-step explanation:
Let, the Width of the rectangle = w in
Now, the length of the rectangle = (w + 4) in
Now, Perimeter = 56 in
Also, we know that
Perimeter of the Rectangle = 2 (Length +Width)
or, 2 (Length +Width) = 56
⇒ 2(w + 4 +w) = 56
or, 4w =56 -8
width = 12 in
So, Length = w + 4 = 12 + 4 = 16 in
Answer:
The absolute value of 4 is just 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hypotenuse² =base² + altitude²
(3x + 4)² = (2x + 1)² + (3x)²
{Use (a+b)² = a² + 2ab + b²}
(3x)² + 2*3x+4 + 4² = (2x)² + 2*2x*1 + 1² + 9x²
9x² + 24x + 16 = 4x² + 4x + 1 + 9x²
9x² + 24x + 16 = 13x² + 4x + 1
0 = 13x² + 4x + 1 - 9x² - 24x - 16
13x² - 9x² + 4x - 24x +1 - 16 = 0
4x² - 20x - 15 = 0
a = 4 ; b =-20 ; c = -15
D = b² - 4ac = (-20)² - 4*4*(-15) = 400 + 240 = 640
√D = √640 = 25.30

x = 5 .66 ; x = -0.66
Ignore x = -0.66 as length of a side cannot be negative
Answer : x = 5.66
To solve for the perimeter first figure out the length and width from the formula of area for the rectangle
A = LxW
A = (14-X)•X
L = (14-X)
W = X
P = 2L + 2W
P = 2(14-X) + 2(X)
P = 28 - 2X + 2X
P = 28.
The perimeter of the rectangle is A. 28.