PLEASE PLEASE PLEASE HELP I NEED HELP WITH THIS :(( i will give brainliest:)

Mathematics

2 answers:

gladu [14]3 years ago

5 0

Answer: pretty sure its 2 but it doesn't go back to 0 so not completely sure

Step-by-step explanation:

solmaris [256]3 years ago

4 0

Answer:

1. ) 2 + (-4) = -2

2. ) 3 + (-2) = 1

3. ) -2 + (-2) = -4

4. ) (-3) + 2 = -1

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Alexeev081 [22]

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3 years ago

3x+4+8x-28=180 what x

Paraphin [41]

The equation simplified (combine like terms) would be 11x+(-24) =180.
Since adding a negative is the same as subtracting a positive, you could also write it as this: 11x-24=180. Next step is isolate the variable, so to do that you need to add 24 to both sides of the equation: 11x-24+24=180+24. This is the same as 11x=204. Now to get only one of the variable, you need to divide both sides by 11. x=18.54 repeating or x=18 6/11. Hope this helped!

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3 years ago

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Every day, Luann walks to the bus stop and the amount of time she will have to wait for the bus is between 0 and 12 minutes, wit

Nana76 [90]

Answer:

a. 341.902.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normal variable:

For n instances of a normal variable, the mean is $n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$