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3 years ago

A company that sells umbrellas was

Mathematics

1 answer:

atroni [7]3 years ago

6 0

1,068 is your answer. There will be 356 in each shipment because 1,424 divided by 4 is 356. And 356 times 3 is 1,068.

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The mean of five numbers is 8. If one of the five numbers is removed, the mean becomes 9. What is the value of the number that w

mestny [16]

Using the mean concept, it is found that the value of the number that was removed was of 4.

The mean of a data-set is given by the <u>sum of all observations in the data-set divided by the number of observations</u>.

The mean of five numbers is 8, hence, the sum of the numbers is given by:

S = 5 x 8 = 40.

If one of the five numbers is removed, the mean becomes 9, hence, the sum of the four numbers is given by:

S = 4 x 9 = 36.

The difference is:

40 - 36 = 4.

Hence, the value of the number that was removed was of 4.

More can be learned about the mean concept at brainly.com/question/25122507

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3 0

2 years ago

Solve the following equation algebraically:

worty [1.4K]

B because 6 times 2 is 12...

4 0

2 years ago

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Is the following shape a square? How do you know

DENIUS [597]

No, because all sides are not congruent. The answer is B.

5 0

3 years ago

Read 2 more answers

Xavier rides his bike 5 1/4 miles or 82% of his goal for the day. What is his goal for the day?

Leno4ka [110]

Use ratio and proportion

5.25/x= 82/100
cross multiply
82 x= 525
x= 6.4 miles

Hope this helps

8 0

2 years ago

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul

Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of Jack in z =F₁z=90.5 N in direction (+z)

Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)

Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)

Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

$F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2} }$

$F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2} }$

$F_{n} = 174.9 N$

7 0

3 years ago