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Crazy boy [7]
3 years ago
7

Lines a, b, c, d, and e are distinct lines in

Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0

Answer: Pretty sure it is perpendicular.

Step-by-step explanation:

If B is perpendicular to A and B and C are parallel, that means C is also perpendicular to A. Since D is perpendicular to C, it is parallel to A. E is perpendicular to D, so it goes back to perpendicular to A.

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Step-by-step explanation:

earning each day=(971.25)/35=$27.75

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The figure shows the dimensions of a room. How much carpet is needed to cover the floor of the room?
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Answer: 24m

Step-by-step explanation:

How much carpet is asking the area and area= LW

so Length(4) x Width(6) = 24

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Can anyone solve this x + 2 ( x + 2 + ( 2 x − 8 ) ) = x + 1 + ( 2 x − 5 ) x + 2 ( x + 2 + ( 2 x - 8 ) ) = x + 1 + ( 2 x - 5 )
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What’s the answer to this one! 15 points!
Phoenix [80]

Answer:

D

Step-by-step explanation:

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Read 2 more answers
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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