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3 years ago

5

Find p(4) p(x) = 3x - 9

1 answer:

never [62]3 years ago

3 0

Answer:

p(4)=3

Step-by-step explanation:

p(4)=3(4)-9=12-9=3

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If 1 yard = 3 feet and 1 mile = 5,280 feet, how many yards are there in 1miles?

slavikrds [6]

1 yard = 3 feet

1 mile = 5,280 feet

So, 1 mile = 5,280/3 yards = 1760 yards

8 0

3 years ago

Х<br> Find the measure of ZXYZ.

sergiy2304 [10]

Answer:

150 Degrees

Step-by-step explanation:

Each color strip represents 10 degrees since a circle is 360 degrees, and there are 36 strips. Since inside of the angle there are 15 strips that means that the angle is 150 degrees.

Hope that helps!

MARK BRAINLIEST!

8 0

2 years ago

Five friends equally shared half of one large pizza and 1/4 of another large pizza. what fraction of each pizza did each friend

attashe74 [19]

1/2 divide by 5= 1/10
1/4 divide by 5= 1/20 so 1/10 is also 2/20+1/20=3/20

so the answer is 3/20 of a pizza
hope this helped and plz leave a thank you

3 0

3 years ago

What is the answer to 2x to the power of 2 +x +1=0

KonstantinChe [14]

Answer:

x=-1

Step-by-step explanation:

x+1=0(squared).

x+1=0 (anything raise to the power 0 is 0

collect like terms =x=-1

therefore x=-1

4 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago