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adoni [48]
3 years ago
6

What is the quotient

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:  -2, 5

<u>Step-by-step explanation:</u>

                 <u>                     3x²  -  2x  + 5  </u>

x² + 3x + 1 ) 3x⁴ + 7x ³ + 2x² + 13x + 5

                - <u>(3x⁴ + 9x³ + 3x²) </u>    ↓     ↓

                           -2x³  -  x²  + 13x    ↓

                        - <u>(-2x³ - 6x²  -  2x) </u>   ↓

                                     5x²  + 15x + 5

                                   -<u> (5x² + 15x + 5)</u>

                                                         0

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The graph of a line is shown below. What is the equation of the line, in slope-intercept form, that is parallel to this line and
Alex_Xolod [135]

Earlier in this chapter we have expressed linear equations using the standard form Ax + By = C. Now we're going to show another way of expressing linear equations by using the slope-intercept form y = mx + b.

In the slope-intercept form you use the slope of the line and the y-intercept to express the linear function.

<span><span>y=mx+b</span><span>y=mx+b</span></span>

Where m is the slope and b is the y-intercept.

Example

Graph the equation

<span><span>y−2x=1</span><span>y−2x=1</span></span>

rewrite in slope-intercept form

<span><span>y=2x+1</span><span>y=2x+1</span></span>

Identify the slope and the y-intercept

m = 2 and b = 1

Plot the point corresponding to the y-intercept, (0,1)

The m-value, the slope, tells us that for each step to the right on the x-axis we move 2 steps upwards on the y-axis (since m = 2)

And once you have your second point you can just draw a line through the two points and extend it in both directions.

You can check to see that the line you've drawn is the correct one by substituting the coordinates of the second point into the original equation. If the equation holds true than the second point is correct.

Our second point = (1, 3)

<span><span>y−2x=1</span><span>y−2x=1</span></span>

<span><span>3−2⋅1=3−2=1</span><span>3−2⋅1=3−2=1</span></span>

Our second point is a solution to the equation i.e. the line we drew is correct.

A line that passes through the origin has a y-intersect of zero, b = 0, and represents a direct variation.

<span><span>y=mx</span><span>y=mx</span></span>

In a direct variation the nonzero number m is called the constant of variation.

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4 0
3 years ago
When you divide a whole number by a fraction with a numerator of how can you find the quotient
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All you have to do is change the whole number to a fraction. Say you have 4 divided by 1/2. All you have to do to make a whole number a fraction is put it over 1. So now you would have 4/1 (4 being the numerator) divided by 1/2. When you divide fractions always remember this; Keep, Switch, Flip. Keep 4/1, Flip the division sign to multiplication, and Flip 1/2 to make it 2/1. Then you multiply the numerators and the denominators. So 4/1 * 2/1 = 8/1. Hope this helped. 
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skad [1K]

Answer:

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8 0
2 years ago
When using the law of sines why cant ssa case result in zero, one, or two
Flura [38]
When using the Law of Sines the ambiguous case can result.
Source:
http://www.1728.org/trigtut2.htm
Scroll to the middle of the page.



8 0
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Read 2 more answers
How to find the point that is equidistant from (5,-5) and (1,1)
torisob [31]
<h3>Answer: (3, -2)</h3>

Explanation:

Your teacher wants you to find the midpoint. This is the point that is in the middle of the two given points. Let's call this M. So the distance from M to (5,-5) will be the same as the distance from M to (1,1)

The x coordinates of (5,-5) and (1,1) are 5 and 1 respectively.

Add them up: 5+1 = 6

Divide by two: 6/2 = 3

The x coordinate of the midpoint is x = 3

Repeat for the y values -5 and 1

Add: -5+1 = -4

Divide in half: -4/2 = -2

The y coordinate of the midpoint is y = -2

So the midpoint is M = (x,y) = (3,-2)

If you were to use the distance formula, you would find that

distance from (5,-5) to (3,-2) = distance from (3,-2) to (1,1)

This is what it means to be "equidistant" (aka "equally distant")

7 0
3 years ago
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