The correct answer is x= -6 let me know if you want to know how I got that or if you needed to know if it is no solution/ infinite/etc..
Answer:
The average velocity of the ball at the given time interval is -122.3 ft/s
Step-by-step explanation:
Given;
velocity of the ball, v = 34 ft/s
height of the ball, y = 34t - 26t²
initial time, t₀ = 3 seconds
final time, t = 3 + 0.01 = 3.01 seconds
At t = 3 s
y(3) = 34(3) - 26(3)² = -132
The average velocity of the ball in ft/s is given as;
![V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s](https://tex.z-dn.net/?f=V_%7Bavg%7D%20%3D%20%5Cfrac%7By%283.01%29-y%283%29%7D%7B3.01%20-3%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%20%5Cfrac%7B34%283.01%29-26%283.01%29%5E2-y%283%29%7D%7B3.01%20-3%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%20%5Cfrac%7B-133.223-y%283%29%7D%7B0.01%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%20%5Cfrac%7B-133.223-%28-132%29%7D%7B0.01%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%5Cfrac%7B-1.223%7D%7B0.01%7D%5C%5C%5C%5CV_%7Bavg%7D%20%3D%20-122.3%20%5C%20ft%2Fs)
Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s
Answer:
Trapezoid Area = [(sum of bases) / (2)] * height)
Trapezoid Area = (10) / (2) * height
15 = 5 * height
height = 3 feet
Step-by-step explanation:
It's a bit hard to explain but I hope this helps