Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=
a=-0.04
b=8.3
c=4.3
x=
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer: 2/3
Step-by-step explanation:
There are three sectors of equal area. 2 is one of the sectors. You can get 3 and 4. There are two total cases out of 3, so it's 2/3
Hope that helped,
-sirswagger21
Answer:
4 1/2 in seconds is 14400
Step-by-step explanation:
Step-by-step explanation:
Given that,
The diameter of the merry-go-round, d = 14 feet
Time taken, t = 6 seconds
Radius, r = 7 feet
The linear speed of the merry-go-round is given by :
Also,
Where
is the angular speed
So,
Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.
Answer:
You can use Gaussian Elimination.
Double both sides of the first equation and add the second equation.
6x + 4y = 8
5x - 4y = 3
---------------
11x = 11
x = 1
5 - 4y = 3
-4y = -2
y = 1/2
Step-by-step explanation: