6x³y + 6xy − 12x² − 12 = 6(xy-2) * (x²+1)
(x²+1) is a factor of 6x³y + 6xy − 12x² − 12
Answer:
Step-by-step explanation:
<u>Given expression:</u>
<u>Find its value when x = 4 and y = 1, substitute:</u>
- 3(4 + 1) + 2*4² + (1 + 1)² =
- 3*5 + 2*16 + 2² =
- 15 + 32 + 4 =
- 51
The answer is 78 because when you add all the numbers it equals 780 and you need to divide the end sum by the amount of numbers added to get it. So in the end there were 10 numbers added to equal 780 so 780\10 equals 78
2 ways
zero product property
easy way
zero product
factor perfect square
m^2-3^2=0
(m-3)(m+3)=0
set each to zero
m-3=0
x=3
m+3=0
m=-3
m=-3 or 3
easy way
add 9 to both sides
m^2=9
sqrt both sides remember to take postive and negative roots
m=+/-3
m=-3 or 3
B is answer