Answer:
$284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.
Step-by-step explanation:
Firstly, to calculate the portions each class should have, we should find the proportion each class takes up.
Hence, let's say A represents Mr. Aceves' class, B represents Mrs. Baca's class, and C represents Mr. Canyon's class.
The total number of box tops collected would be 3760 + 2301 + 1855 = 7916 box tops.
Therefore, the total proportions would be:
A = 
B = 
C = 
Hence, we can finally multiply these proportions with the total prize to find the appropriate division:
Mr. Aceves' class gets 
.
Mrs. Baca's class gets 
.
And Mr. Canyon's class gets 
.
Finally, $284.99 should go to Mr. Aceves’ class, $174.41 should go to Mrs. Baca’s class, and $140.60 should go to Mr. Canyon’s class.
Hope this helped!
Answer:
10 of 1
Step-by-step explanation:
just think about it
Answer:
B y=8x
Step-by-step explanation:
A proportional relationship must go through the point x=0, y=0 and be in the form y=kx where x is a constant
A) y = x^8
B) y = 8 x
C) y = x^8 + 8
D) y = 8 x + 8
The only points that is in the form y= kx is option B
C and D do not go through x=0, y=0 and A is not in the form y=kx where k is a constant
Answer:
option D 12 is correct..
in second question the student didn't multiply -3 with 4. that's the mistake he did.
hope it helps
Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
