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GaryK [48]
2 years ago
9

PLEASE SOMEONE HELP ME WITH THIS! I'LL GIVE BRAINLIEST TO WHOEVER HELPED!!!

Mathematics
1 answer:
allochka39001 [22]2 years ago
5 0

Step-by-step explanation:

C4H6O3 + H2O => 2C2H4O2

C2H4 + 3O2 => 2CO2 + 2H2O

C4H10O + 6O2 => 4CO2 + 5H2O

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5 31/30 or 181/30

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- 30 = 12 – 6r<br><br> Pls help
oee [108]

Answer: r = 7

Step-by-step explanation:

Subtract 12 from both sides to isolate the r variable. You have -42 = -6r. Divide both sides by -6 to get r by itself and you get r = 7. Verify by substituting 7 as the r value and solving the equation.

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A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises
Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft

Period = 12 hours

and we know that; period = 2π/b

so

12 = 2π/b

12b = 2π

b = 2π / 12

b = π/6

Standard equation for simple harmonic is; y = asin(bt)

we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

7 0
3 years ago
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