Answer:
<h2>n = 8</h2>
Step-by-step explanation:
Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d
a = first term of the sequence
n = number of terms
d = common difference.
Given the first element a = 2 and 22nd to be 14
T22 = a+(22-1)d = 14
a+21d = 14
Substtuting a = 2 into the equation to get d
2+21d = 14
21d = 12
d = 12/21
d = 4/7
The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;
Tn = 2+(n-1)4/7
Given Tn = 6
6 = 2+(n-1)4/7
6 = 2+4/7 n - 4/7
6-2+4/7 = 4/7 n
32/7=4/7 n
32 = 4n
n = 32/4
n = 8
Since the diameter of the cylinder is 10, its radius is half that, or 5, thus
{-2x-5y=13
<u>{2x-5y=17 </u>(+)
<em /> -2x+2x-5y-5y=13+17
-10y=30 /:(-10)
y=-3
2x-5y=17
2x-5*(-3)=17
2x+15=17
2x=2
x=1
<em>Solution: (1; -3)</em>
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Y intercept when x =0
<span> y=-x+3
y = -0 +3
y = 3
</span><span> the slope is -1 </span>
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