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jarptica [38.1K]
3 years ago
8

Multiple choice please help emergency

Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer:

5000 N

Step-by-step explanation:

Given,

Mass ( m ) = 20 kg

Acceleration ( a ) = 250 m/s^2

To find : Force ( F ) = ?

Formula : -

F = ma

F

= 20 x 250

= 5000 N

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What is the sum of the sequence 152,138,124, ... if there are 24 terms?
N76 [4]

Answer: -216

Step-by-step explanation:

To solve the exercise you must use the formula shown below:

Sn=\frac{(a_1+a_n)n}{2}

Where:

a_1=152\\a_n=a_{24}

You should find  a_{24}

The formula to find it is:

a_n=a_1+(n-1)d

Where d is the difference between two consecutive terms.

d=138-152=-14

Then:

a_{24}=152+(24-1)(14)=-170

Substitute it into the first formula. Therefore, you obtain:

S_{24}=\frac{(152-170)(24)}{2}=-216

3 0
4 years ago
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nick loaned 550 to his best friend. the friend agreed to pay it back the amount borrowed plus 12% interest. what was the total a
lina2011 [118]
$616 because 550 times .12(12% as decminal) is 66. $66 plus $550 is $616
3 0
3 years ago
What are the factors of m2 – 12m + 20?
amm1812
M² - 12m + 20

m² ⇒ m * m
20 ⇒ - 10 * -2

(m - 10)(m - 2)
m(m - 2) - 10(m-2)
m² - 2m - 10m + 20
m² - 12m + 20

m - 10 = 0
m = 10

m - 2 = 0
m = 2

5 0
4 years ago
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Sophia determined that the expression Negative (4 x minus 5) + 2 (x minus 3) is equivalent to –2x – 5 by using the steps below.
CaHeK987 [17]

Answer:Hope This Helps ☺️

Step-by-step explanation:

She is not correct because she did not substitute the same number in both expressions in Step 1

Step-by-step explanation:

CASE 1: substitute 1 for x to both sides of the equations

L.H.S

-(4x-5)+2(x-3)

-(4 (1) - 5)+ 2(1-3) = - (-1) + 2(-2) = 1 - 4 = -3

R.H.S

-2x - 5

-2(1) - 5 = -2-5 = -7

Hence for x= 1

-(4x-5)+2(x-3) ≠ -2x -5

Because -3 ≠ -7

CASE 2: substitute -1 for x to both sides of the equations

L.H.S

-(4x-5)+2(x-3)

-(4 (-1) - 5)+ 2(-1-3) = - (-9) + 2(-4) = 9 - 8 = 1

R.H.S

-2x - 5

-2(-1) - 5 = 2-5 = -3

Hence for x= -1

-(4x-5)+2(x-3) ≠ -2x -5

Because 1 ≠ -3

Answer:

She is not correct because she did not substitute the same number in both expressions in Step 1

3 0
3 years ago
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In imaginary numbers can you multiply two radicals that have negative values under them that do not square to whole numbers
ElenaW [278]
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .

Take, for example, the commonly known "imaginary number":  "i" ;  which represents the "imaginary number" ;  " √-1 " .

Since:  "i = √-1" ; 

Note that:   " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
__________________________________________________
7 0
4 years ago
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