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3 years ago

7

The relationship between the amount of tomato sauce and tomato paste needed for a pasta sauce recipe is shown in the following g

raph.

1 answer:

adoni [48]3 years ago

3 0

Answer:

none of the above

Step-by-step explanation:

You might be interested in

The sum of 4 consecutive integers is 40 what is the third number in this sequence?

Dmitry [639]

Let's represent the numbers by : x, x+1, x+2, x+3
x+x+1+x+2+x+3=40 The third number in the sequence is x+2
4x+6=40 8.5+2=10.5
4x+6-6=40-6 Therefore the third number in the sequence is
4x=34 10.5
4x/4=34/4
x=8.5

3 0

3 years ago

Help please word problem...show work please

Alona [7]

A) you must plug in 50 for variable F and solve for C

C= $\frac{5}{9}$ (50-32)
C= $\frac{5}{9}$ (18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius

B) you must solve the equation for F

C= $\frac{5}{9}$ (F-32)
C/ $\frac{5}{9}$ =F-32
C/ $\frac{5}{9}$ +32=F
F= C/ $\frac{5}{9}$ +32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F= $\frac{9}{5}$ C +32

now you just plug in 50 for the variable C in the new equation

F= $\frac{9}{5}$ (50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

6 0

3 years ago

Each side of a cube is 2 inches long what’s the volume of the cube

Kaylis [27]

Answer:

Step-by-step explanation:

The volume of a cube is s*s*s or s^3 where s = the length of a side (2 in this case).

V = s^3

V = 2^3

V = 2*2*2

V = 8 cu in or 8 in^3

4 0

3 years ago

(10 points)Assume IQs of adults in a certain country are normally distributed with mean 100 and SD 15. Suppose a president, vice

vesna_86 [32]

Answer:

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Step-by-step explanation:

To solve this question, we need to use the binomial and the normal probability distributions.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability the president will have an IQ of at least 107.5

IQs of adults in a certain country are normally distributed with mean 100 and SD 15, which means that $\mu = 100, \sigma = 15$

This probability is 1 subtracted by the p-value of Z when X = 107.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{107.5 - 100}{15}$

$Z = 0.5$

$Z = 0.5$ has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 probability that the president will have an IQ of at least 107.5.

Probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

First, we find the probability of a single person having an IQ of at least 130, which is 1 subtracted by the p-value of Z when X = 130. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{130 - 100}{15}$

$Z = 2$

$Z = 2$ has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

Now, we find the probability of at least one person, from a set of 2, having an IQ of at least 130, which is found using the binomial distribution, with p = 0.0228 and n = 2, and we want:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.9772)^{2}.(0.0228)^{0} = 0.9549$

$P(X \geq 1) = 1 - P(X = 0) = 0.0451$

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

What is the probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130?

0.3085 probability that the president will have an IQ of at least 107.5.

0.0451 probability that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

Independent events, so we multiply the probabilities.

0.3082*0.0451 = 0.0139

0.0139 = 1.39% probability that the president will have an IQ of at least 107.5 and that at least one of the other two leaders (vice president and/or secretary of state) will have an IQ of at least 130.

8 0

2 years ago

Write 80 : 88 in the form n : 1

storchak [24]

Step-by-step explanation:

To write the ratio into the form of n:1, divide 80 and 88 by 88.

$80 \div 88 = 0.91 \: rounded$

$88 \div 88 = 1$

The ratio in the form is 0.91:1 (rounded)

3 0

2 years ago

Read 2 more answers