14 b + 9 b – 4 – 12b Help meh pls Xd

Mathematics

2 answers:

trasher [3.6K]2 years ago

8 0

Answer:

Simplify the expression.

11 b − 4

Step-by-step explanation:

PSYCHO15rus [73]2 years ago

7 0

$\huge\text{Hey there!}$

$\large\text{14b + 9b - 4 - 12b}\\\\\large\text{COMBINE the LIKE TERMS}\\\\\large\text{(14b + 9b - 12b) + (-4)}\\\\\large\text{(14b + 9b - 12b) = 23b - 12b = \bf{11b}}\\\\\large\text{-4 = \bf{-4}}\\\\\large\text{\bf{= 11b - 4}}\\\\\\\boxed{\boxed{\large\text{Answer: \bf{11b - 4}}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

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Show your work AND the answer a research showed that 45% of sixth graders have dogs for pets 35% have cats 10% have fish and 5%

Arturiano [62]

Answer: 600 students

Step-by-step explanation:

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3 years ago

If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei

MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is ${11 \choose 3} = 165 .$ As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is ${7 \choose 3} = 35$ . Thus, there are only 35 ways to distribute the blackboards in this case.