Process: x^2 -12x +36 =0
(X-6) ^2 =0
X-6=0
Result: x=6
Point slope form: y-y1 = m(x-x1)
Find slope: (y2-y1)/(x2-x1)
(1-5)/(9+3) = -4/12 = -1/3
Point slope equation: y+5 = -1/3(x+3)
Slope intercept: y = -1/3x - 1 + 5
Final slope int equation: y = -1/3x + 4
Answer:
The calculated value z= 0.0063 does not fall in the critical region so we fail to reject the null hypothesis. And accept that the valve does not perform above the specifications.
Step-by-step explanation:
Given that
Population mean= μ = 8.0
Sample mean= x`= 8.1
Sample size= n= 250
Sample standard deviation= s= 1.00
Significance level= ∝ =0.01
The null hypothesis and alternate hypothesis are
H0: μ < 8.0
Ha: μ ≥ 8.0 One tailed test
The claim is that the valve perform above the specifications
The critical value at 0.01 significance level for one tailed test is z > ±2.33
The test statistic z is used
z= x`- μ/ σ/√n
Z= 8.1-8.0/ 1/√250
z= 0.1/1/15.811
z= 0.0063
The calculated value z= 0.0063 does not fall in the critical region so we fail to reject the null hypothesis.
Answer:
v=± 47=±6.8557
Step-by-step explanation:
(1): "v2" was replaced by "v^2".
(2) Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation: v^2-(47)=0
16 or 8 what i did was multiplied it by .5
