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Nostrana [21]
4 years ago
6

Six times the sum of three consecutive odd integers is -18. What are the integers?

Mathematics
2 answers:
blondinia [14]4 years ago
7 0

Answer:

1, -1, -3

Step-by-step explanation:

6(x+x+2+x+4)=-18

6(3x+6)=-18

18x+36=-18

18x=-54

x=-3

so x=-3, x+2=-1, and x+4=1

kati45 [8]4 years ago
7 0

Answer:

-3, -1 and 1.

Step-by-step explanation:

If we define a number as x, the next odd number is x+2, and the next is x+4, so three consecutive odd integers are: x, x+2 and x+4.

the sum of these consecutive numbers is:

x+x+2+x+4\\=3x+6

and six times that sum:

6(3x+6) which is equal to: 18x+36

and the problem statement indicates that 6 times the sum of the three consecutive odd integers is equal to -18, so:

18x+36=-18

clearing for x:

18x=-18-36

18x=-54

x=\frac{-54}{18} =-3

so if x=-3, x+2=-1 and x+4=1

the three integers are: -3, -1 and 1.

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