Question

Six times the sum of three consecutive odd integers is -18. What are the integers?

Answer 1

Answer:

1, -1, -3

Step-by-step explanation:

6(x+x+2+x+4)=-18

6(3x+6)=-18

18x+36=-18

18x=-54

x=-3

so x=-3, x+2=-1, and x+4=1

Answer 2

Answer:

-3, -1 and 1.

Step-by-step explanation:

If we define a number as $x$, the next odd number is $x+2$, and the next is $x+4$, so three consecutive odd integers are: $x$, $x+2$ and $x+4$.

the sum of these consecutive numbers is:

$x+x+2+x+4\\=3x+6$

and six times that sum:

$6(3x+6)$ which is equal to: $18x+36$

and the problem statement indicates that 6 times the sum of the three consecutive odd integers is equal to $-18$, so:

$18x+36=-18$

clearing for x:

$18x=-18-36$

$18x=-54$

$x=\frac{-54}{18} =-3$

so if $x=-3$, $x+2=-1$ and $x+4=1$

the three integers are: -3, -1 and 1.