It would be 11 cups your welcome
( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.
<h3>What is inequality?</h3>
The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than’
Finding the solution for the inequality is as follows:-
y ≤ x² +x-4 by putting x and y equal to 0.
0 ≤ 0 + 0 -4
0 ≤ - 4
This is incorrect so (0,0) can not be the solution for this inequality.
y < x²+2x+1.
0 < 0 + 0 + 1
0 < 1
This inequality is showing the solution for (0,0)
Therefore ( 0,0 ) is not the solution of the first inequality y≤x² +x-4 but ( 0,0) is the solution for the second inequality y <x²+2x+1.
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Answer: what grade are you in
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Step-by-step explanation:
=d/dx((t^4-6)^3) * (t^3+6)^4 + d/dx((t^3+6)^4) * (t^4-6)^3
=3*(t^4-6)^2 * (t^3+6)^4 * d/dx(t^4-6) + 4*(t^3+6)^3 * (t^4-6)^3 * d/dx(t^3+6)
=3*(t^4-6)^2 * (t^3+6)^4 * 4t^3 + 4*(t^3+6)^3 * (t^4-6)^3 * 3t^2
Simplify that if youd like
Answer:
D
Step-by-step explanation:
(0, 0) (0, 1) (1, 2) (1, 3)
For it to be a function each x value should have one y value.
There are two 0's for x and two 1's for x. This is how you can tell it's not a function.
