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Andre45 [30]
3 years ago
13

Please help, im two weeks behind on my math ):

Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

the surface of area is 14cm to 2cm to 6cm please rate my answer

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Step-by-step explanation:

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A right triangle has legs of length 6 and 11. What is the length of the hypotenuse?
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Simplify : x ^ (1/3) * (x ^ (1/2) + 2x ^ 2)
Rudiy27

Answer:

x^{\frac{1}{3}}\:\times \left(x^{\frac{1}{2}}\:+\:2x^2\right)=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

Step-by-step explanation:

x^{\frac{1}{3}}\:\times \left(x^{\frac{1}{2}}\:+\:2x^2\right)

Let us simplify the expression

x^{\frac{1}{3}}\:\times \left(x^{\frac{1}{2}}\:+\:2x^2\right)

\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac

a=x^{\frac{1}{3}},\:b=x^{\frac{1}{2}},\:c=2x^2

so

=x^{\frac{1}{3}}x^{\frac{1}{2}}+x^{\frac{1}{3}}\times \:2x^2

=x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

so the expression becomes

=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

Thus,

x^{\frac{1}{3}}\:\times \left(x^{\frac{1}{2}}\:+\:2x^2\right)=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

5 0
3 years ago
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