Please help, im two weeks behind on my math ):

PLEASE HELP ASAP AND NO VIRS!

Kay [80]

Answer:

C) 84

Step-by-step explanation:

6 0

3 years ago

Please help pictures below!

qaws [65]

the frist one is 7the second one is 33

4 0

3 years ago

The perimeter of the patio is 64 feet. The width of the patio is (x+2) feet and the length of the patio is (x+6) feet. What are

ValentinkaMS [17]

The formula for the perimeter is P = 2w + 2l, where w is the width and l is the length. It is given that the width = (x+2) and the length = (x+6). Therefore, we can make this equation:

P = 2w + 2l

64 = 2(x+2) + 2(x+6) ⇒ Distributive property

⇒ 64 = 2x + 4 + 2x + 12 ⇒ Combine like terms

⇒ 64 = 4x + 16 ⇒ Subtract 16 from both sides

⇒ 48 = 4x ⇒ Divide both sides by 4

⇒ x = 12

Then, we use x = 12 and substitute it in to find the length and width

Width = (x+2) = (12+2) = 14

Length = (x+6) = (12+6) = 18

The dimensions of the patio is 14 by 18

5 0

2 years ago

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

2 years ago

Ticketd to the school play cost $11 for adults and $6 for children. What expression can be used to find the toyal cost for x adu

Makovka662 [10]

Answer:221

Step-by-step explanation:

4 0

3 years ago