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3 years ago

A = pq^2r make r the subject

Mathematics

1 answer:

ollegr [7]3 years ago

5 0

Answer: r=a/pq^2

Step-by-step explanation:

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Please help it is midpoint

almond37 [142]

(15,9)
(1,-9)

$\\ \rm\hookrightarrow (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$\\ \rm\hookrightarrow (x,y)=\left(\dfrac{15+1}{2},\dfrac{9-9}{2}\right)$

$\\ \rm\hookrightarrow (x,y)=\left(\dfrac{16}{2},\dfrac{0}{2}\right)$

$\\ \rm\hookrightarrow (x,y)=(8,0)$

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3 years ago

Read 2 more answers

What is the slope of this equation?y= -1/2x −3 Question 2 options: 0 -3 -1/2

storchak [24]

Answer:

-1/2

Step-by-step explanation:

In the equation y=mx+b..

y and x are the coordinates that go into your function

m is the slope

and b is the y intercept

looking at y=-1/2x-3 i can tell that -1/2 is in the place of m which is slope, and -3 is the y intercept.

8 0

3 years ago

If the length of a rectangle is (x+5) and the width is (x+2), what is the area of the rectangle?

BARSIC [14]

Answer: x^2+7x+10

Step-by-step explanation:

8 0

3 years ago

Look at picture, please I need help on this question

Sergio [31]

Answer:

Step-by-step explanation:

look at graph for answers, vertex is at the point

7 0

3 years ago

The numerical course grades in a statistics course can be approximated by a normal model with a mean of 70 and a standard deviat

Naily [24]

Answer:

A = 82.82

B = 72.53

C = 61.58

D = 53.55

Step-by-step explanation:

First, determine the percentile at which the cutoff grade in each letter grade interval falls on and find the equivalent z-score:

A: (100-10) = 90-th percentile

z-score = 1.282

B: (100-10-30) = 60-th percentile

z-score = 0.253

C : (100-10-30-40) = 20-th percentile

z-score = -0.842

D: (100-10-30-40-15) = 5-th percentile

z-score = −1.645

The value 'X' for each cutoff can be found by applying the z-score equation:

$z= \frac{X- \mu }{SD}$

Where μ is the mean and SD is the standard deviation

Therefore, the cutoffs are:

$1.282= \frac{X(A)- 70}{10}\\X(A) = 10*1.282 +70\\X(A) = 82.82\\\\0.253 = \frac{X(B)- 70}{10}\\X(B) = 10*0.253 +70\\X(B) = 72.53\\\\0.253 = \frac{X(C)- 70}{10}\\X(C) = 10*-0.842 +70\\X(C) = 61.58\\\\0.253 = \frac{X(D)- 70}{10}\\X(D) = 10*-1.645 +70\\X(D) = 53.55\\$

6 0

3 years ago