A = pq^2r make r the subject

Sesame Company purchased a computer system for $74,000 on January 1, 2018. It was depreciated based on a 7-year life and an $18,

amm1812

Answer: $24000

Step-by-step explanation:

Depreciation for 2018 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation for 2019 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation up to 2019 = $8000 + $8000 = $16000

Book value at end of 2019 = $74000 - $16000 = $58000

Revised residual value = $10,000

Number of remaining years = 4-2 = 2 years

Depreciation expensed for 2020 will be:

= ($58000 - $10,000) / 2

= $48000/2

= $24000

7 0

2 years ago

Here have some points

kozerog [31]

Answer:

Cheers bro ;)

5 0

2 years ago

Read 2 more answers

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

ANSWER:

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

SOLUTION:

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

Which expression is represented by the diagram? ( Marked 1-4, I can't paste the question.)

wel

Answer:

-6-(-1)

Step-by-step explanation:

Since all the boxes are negative, and there are 6 boxes, the first part of the equation is -6. Then since the last box is being taken away, we are subtracting it. The last box is still negative though so the last part is -1. Since -6 subtracted by -1 is -6-(-1), the answer is:

-6-(-1)

8 0

3 years ago

Assume that the probability of any newborn baby being a girl is one half

asambeis [7]

Answer:

1/32

Step-by-step explanation:

P(0 girls)

= P(5 boys)

= (1 − ½)⁵

= 1/32

7 0

3 years ago