Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
-ab + 4a + 3 - (-8ab + 6)......distribute the - thru the parenthesis
-ab + 4a + 3 + 8ab - 6.....now just combine like terms
7ab + 4a - 3 <===
They are called the order of operations, or PEMDAS. Hope this helps!
The interior angles of a triangle need to be equal to 180°, so to solve this you need to figure out how many degrees you need to get 180°.
46 + 61 = 107
180 - 107 = 73
The measure of the third angle is B. 73°.
