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3 years ago

Which expression is equivalent to the one below?

Mathematics

1 answer:

Yanka [14]3 years ago

3 0

Answer:

The answer is -5 + 1/8

Step-by-step explanation:

If you use the distributive property, which is mandatory with parenthesis you first multiply -1/2 by 10 which is -5. The next step is to multiply -1/2 by 1/4 which is -0.125 or -1/8, which the closest answer to it is -5 + 1/8. Hope this helps :)

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The functions f and g are defined by these sets if input and output values.

erastovalidia [21]

(x,y)
x=input
y=output
example
we see
g=(1,2)
theefor
g(1)=2

a.
f(4)=1
g(1)=2
g(f(4))=2

b.
g(-2)=4
f(4)=1
f(g(-2))=1

c.
f(3)=5
g(5)=5
f(5)=0
f(g(f(3)))=0

5 0

3 years ago

A particle is moving along the number line so that its distance (in meters) from the origin at any time t (in seconds) is given

Black_prince [1.1K]

Answer:

The velocity is 17 m/s

Step-by-step explanation:

To find the velocity, we find the first differential of the displacement

That will be

S’(t) = 16t + 1/t

We simply proceed to replace t with 1

That will give;

16(1) + 1/1

= 16 + 1 = 17 m/s

8 0

3 years ago

The table shows the grades that science students earned on the last test. a:17 b:25 c:24 d:12 f:2 What percent of students recei

Molodets [167]

Answer:

0.525 %

Step-by-step explanation:

there is a total of 80 students and 42 received a A or B so 42/80 = 0.525

Hope this helps!

8 0

3 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$

$f'(x)=12x^2+26x-12$

$f''(x)=24x+26$

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here: x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

$24(-2.6)+25$

$-37.5$

So we have a maximum at x=-2.6.

$24(.4)+25$

$9.6+25$

$34.6$

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

$y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56$

I'm shoving this into a calculator:

$y=-58.4654411$

So the approximate relative minimum is (0.4,-58.5).

If you graph $y=4x^3+13x^2-12x-56$ you should see the graph taking a dip at this point.

3 0

3 years ago

Determine the end behavior of the polynomial function. f(x)=-3x^4-2x^3+2x^2+ 3x +5 a) falls to the left and rises to the right b

Molodets [167]

Answer:

Option b is correct

Step-by-step explanation:

In order to check the end behavior of a polynomial function we just check the leading term and its coefficient and the procedure is as follows:

Here we can see that highest exponent of the polynomial function is 4

therefore degree of the polynomial is 4. and therefore $-3x^4$ is leading term.

because of even degree it will be same from both ends that is either both sides rises or both sides falls. Since number in the front of leading is negative therefore it falls at both ends. that is falls to the left and falls to the right.

therefore option b is correct.

8 0

4 years ago