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goldenfox [79]
3 years ago
5

Pls answerrrrrr<3333

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

(x+6)(x+10)

Step-by-step explanation:

Break the expression into groups, =(x2+6x)+(10x+60)

Factor out x from x2+6x:     x(x+6)

Factor out 10 from 10x+60:     10(x+6)

=x(x+6)+10(x+6)

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Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


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