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3 years ago

Write a whole number that is greater than 10910099999

Mathematics

2 answers:

Law Incorporation [45]3 years ago

4 0

Answer:

109100999999

Step-by-step explanation:

floor gang aooh sub to pewdiepie

Airida [17]3 years ago

3 0

The answer to this question is 2000099000000

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Helppppp PLEASEEEEE VERY ARGENTTTT

vekshin1

Answer:

D; x -y = 22

3x + 2y = 246

Step-by-step explanation:

Let us have the bigger number as x and the smaller as y

The difference between the two is 22

Thus, we have it that;

x - y = 22

twice the smaller number; 2(y) added to thrice the larger 3(x) equals 246

3x + 2y = 246

So we have the two equations as;

x -y = 22

3x + 2y = 246

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3 years ago

What type a problem can be. Using the greatest common factor

sergeinik [125]

The word greatest in a word problem tells you to do GCF and the word least in a problem means to use the LCM

6 0

3 years ago

Analyze the diagram below and answer the question that follows.

pshichka [43]

Answer:

A:sin (J) >cos (L)

Step-by-step explanation:

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7 0

3 years ago

It takes 16 minutes for 9 people to paint 8 walls . How many minutes does it take for 4 people to paint 6 walls?

Soloha48 [4]

Answer:

27 minutes to complete the painting of 4 walls

Step-by-step explanation:

since 16m with 9p --> 8 walls

x minutes with 4p --> 6 walls?

let x= minutes

6 walls painted=(8/144 walls painted per minute)x

simplify

x= 6 divided by (8/144)

x=108 minutes (to complete 6 walls)

108/4=

27 minutes to complete the painting of 4 walls

4 0

3 years ago

Read 2 more answers

Please help me answer this question

ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} \div (1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-(e^{x} -e^{-x})}{e^{x} +e^{-x}} \div (\frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} })$

$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

$=\frac{e^{-x}+e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

#SPJ1

6 0

2 years ago