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3 years ago

Use properties to rewrite the expression to be easier to solve explain (13+4.63)+7.4

Mathematics

1 answer:

Nuetrik [128]3 years ago

8 0

Answer

(13+4) + (4.63+7.4)

Step-by-step explanation:

Use the commutative property to put the decimals together. Use the associative property to group the decimals and numbers together as shown in the answer.

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Lynna [10]

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

<h3>What is speed?</h3>

Speed is the ratio of distance to time.

For Jada:

Speed = 2 miles / 12 minutes = 0.167 miles per minute

For Jada cousin:

Speed = 1 mile / 24 min = 0.0417 miles per minute.

Hence, in 15 minutes:

Jada distance = 15 min * 0.167 miles per minute = 2.5 miles

Jada cousin distance = 15 min * 0.167 miles per minute = 0.625 miles

In 15 minutes, Jada would have covered about 2.5 miles, while the cousin would have covered 0.625 miles.

Find out more on speed at: brainly.com/question/4931057

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2 years ago

EMERGENCY OOF HELP WITH MATH PIZZZ<br><br> 5 + x^2= 2x^2+ 13<br><br> Provide steps and thanks

galben [10]

Answer:

false statement

Step-by-step explanation:

5+x^2=2x^2+13

5+x^2-2x-13=0

-8+x^2-2x^2=0

-8-x^2=0

-x^2=8

x^2=-8

this statement is false for any value of x because the power function with an even exponent is always postive or 0

4 0

3 years ago

Four polynomials are shown below:

Tatiana [17]

The appropriate choice is
Polynomial B. -3x⁴ +5x³ +5

_____
C and D are not trinomials. (They have 4 terms, not 3.) A is 5th degree, not 4th.

8 0

3 years ago

find the coordinates of the point P on the parabola y=1-x^2 with domain 0≤x≤1 that minimize the area of the triangle enclosed by

coldgirl [10]

Let point P be with coordinates $(x_0,y_0).$ Find the equation of the tangent line.

1. If $y=1-x^2,$ then $y'=-2x.$

2. The equation of the tangent line at point P is

$y-y_0=-2x_0(x-x_0).$

Find x-intercept and y-intercept of this line:

when x=0, then $y=y_0+2x_0^2;$
when y=0, then $x=\dfrac{y_0}{2x_0}+x_0=\dfrac{y_0+2x_0^2}{2x_0}.$

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

$A=\dfrac{1}{2}\cdot (2x_0^2+y_0)\cdot \left(\dfrac{y_0+2x_0^2}{2x_0}\right)=\dfrac{(y_0+2x_0^2)^2}{4x_0}.$

Since point P is on the parabola, then $y_0=1-x_0^2$ and

$A=\dfrac{(1-x_0^2+2x_0^2)^2}{4x_0}=\dfrac{(1+x_0^2)^2}{4x_0}.$

Find the derivative A':

$A'=\dfrac{2(1+x_0^2)\cdot 2x_0\cdot 4x_0-4(1+x_0^2)^2}{16x_0^2}=\dfrac{12x_0^4+8x_0^2-4}{16x_0^2}.$

Equate this derivative to 0, then

$12x_0^4+8x_0^2-4=0,\\ \\3x_0^4+2x_0^2-1=0,\\ \\D=2^2-4\cdot 3\cdot (-1)=16,\ \sqrt{D}=4,\\ \\x_0^2_{1,2}=\dfrac{-2\pm4}{6}=-1,\dfrac{1}{3},\\ \\x_0^2=\dfrac{1}{3}\Rightarrow x_0_{1,2}=\pm\dfrac{1}{\sqrt{3}}.$

And

$y_0=1-\left(\pm\dfrac{1}{\sqrt{3}}\right)^2=\dfrac{2}{3}.$

Answer: two points: $P_1\left(-\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right), P_2\left(\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right).$

6 0

3 years ago

100 POINTS HELP ME!!!!!!!

trasher [3.6K]

Given : A theater company has raised $930.75 by selling 25 floor seat tickets. Each ticket costs the same.

To Find : Write an equation with a variable that can be solved to correctly find the price of each ticket.

the price of each floor seat ticket.

Solution:

Let say price of each ticket = x $

then price of 25 tickets = 25x $

Price of 25 tickets = $930.75

Equating both

25x = 930.75

is required equation

25x = 930.75

Divide both sides by 25

=> x = 930.75/25

=> x = 37.23 $

price of each floor seat ticket. = 37.23 $

also, there was another question like this.

3 0

3 years ago

Read 2 more answers