2x + 2y=132
xy=1080
Let x=1080/y
2160/y + 2y=132
2y^2 - 132y +2160=0
2(y^2-66y+1080)=0
2(y-30)(y-33)=0
y=30 or y=33
(36,30) or (30,36)
So... x=30,36 and y=36,30. Either way, the answer is 30 by 36 or 36 by 30.
Answer:
how many numbers have absolute value 3? zero is your answer
how many numbers have absolute value a, if a>0? your answer is also zero
Step-by-step explanation:
Quadrant 4 is the correct answer, and it's the only
Answer:
<em>x = 5</em>
Step-by-step explanation:
5(x + 4) - 8 = x + 32
5x + 20 - 8 = x + 32
5x + 12 = x + 32
5x - x + 12 = 32
5x - x = 32 - 12
4x = 32 - 12
4x = 20
x = 5
Hope this helped! :)
