![\frac{2(a-3)}{(3+a)(3-a)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%28a-3%29%7D%7B%283%2Ba%29%283-a%29%7D)
Step-by-step explanation:
This can be written as;
![\frac{8}{9-a^2} *\frac{a^2-6a+9}{4a^2-4a-24}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B9-a%5E2%7D%20%2A%5Cfrac%7Ba%5E2-6a%2B9%7D%7B4a%5E2-4a-24%7D)
Perform factorization
9-a²=difference of squares formula
(3+a)(3-a)
4a²-4a-24
4(a²-a-6)
4(a²-3a+2a-6)
4(a(a-3)+2(a-3))
4((a+2)(a-3))
a²-6a+9
a²-3a-3a+9
a(a-3)-3(a-3)
(a-3)(a-3)
Rewrite the operation as;
![\frac{8}{(3+a)(3-a)} *\frac{(a-3)(a-3)}{4((a+2)(a-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B%283%2Ba%29%283-a%29%7D%20%2A%5Cfrac%7B%28a-3%29%28a-3%29%7D%7B4%28%28a%2B2%29%28a-3%29%7D)
cancel common to remain with;
![\frac{2(a-3)}{(3+a)(3-a)}](https://tex.z-dn.net/?f=%5Cfrac%7B2%28a-3%29%7D%7B%283%2Ba%29%283-a%29%7D)
Learn More
Factorization : brainly.com/question/11930808
Keywords : Operation
#LearnwithBrainly
Add 9 to both sides to get the x-value alone
x-9=-5
x=4
Answer:
f(x)=x-5 is a linear function
Step-by-step explanation:
so there are no restrictions to what x can be. The domain is all real numbers. In interval notation, we show that is can be anything from negative infinity through infinity like this: This says that the lower limit of the domain is negative infinity and the upper limit is positive infinity.
Well all you do is times 25,15, and 10