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snow_tiger [21]
3 years ago
11

Chuck built a garden in the shape of a rectangle in his backyard. The width of the garden is 7 feet and the length of the garden

is 24 feet. He built a walking pathway along the diagonal of the rectangular garden. Which measurement represent the length of the walking path in feet?
Mathematics
1 answer:
Nastasia [14]3 years ago
5 0
The answer is 25 because of the Pythagorean theorem. 49+576=625 625 squared=25
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The figure below is a net for a right rectangular prism. Its surface area is 104 ft2 and
kiruha [24]

Answer:

12+12+10+10=44

104-44=60

60÷2=30

30 is the surface area of A

30÷6=5

5 is a missing dimention

4 0
3 years ago
Is this a function <br><br> Yes or no
Bingel [31]

Answer:

yes.

Step-by-step explanation:

by performing the vertical line test, you can see that the line only goes through one point, so it is a function.

5 0
3 years ago
Read 2 more answers
The corrdinates of point h are 3,-2 wich point has the coordinates -3,2​
timofeeve [1]

Answer: h

Step-by-step explanation: since point h corrdinates of 3,-2 and u wanna find 3,-2 the answers is in the question

8 0
3 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
Which best describes the relationship between the line that passes through the points (-9, -7) and (-12, -2) and the line
o-na [289]

Answer:

A

Step-by-step explanation:

The equation of the line that passes through the points (-9,-7) and (-12,-2) is

y = -5/3x-22

and

equation of the line that passes through the points (1, 9) and (6, 6) is

y = -3/5x+48/5

clearly it is not the same line,

\frac{-5}{3}.\frac{-3}{5}  \neq -1 (lines are not perpendicular)

\frac{-5}{3}\neq \frac{-3}{5} (not parallel)

8 0
2 years ago
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