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2 years ago

Please help asap!!!!!

Mathematics

1 answer:

emmasim [6.3K]2 years ago

3 0

43 maybe? And if I’m wrong in advance-Sorry

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-7x + 11 = 19 - X<br><br>solve for x

Vlad1618 [11]

Answer:

x = -4/3

Have a nice day.

7 0

2 years ago

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A researcher is exploring the notion that there is an economy of scale in raising children. While having one child might add to

trasher [3.6K]

Answer:

The probability is $G = 85%$

Step-by-step explanation:

From the question we are told that

The percentage of parents that have one child under 18 in their homes is k = 15%

The percentage of parents that have two children is T = 65%

The percentage of parents that have three or more children is Y = 20%

Generally the probability that any given family who is selected have two or more children at home is mathematically evaluated as

$G = T + Y$

=> $G = 65% + 20%$

=> $G = 85%$

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2 years ago

2x = 17 is a linear function<br> True<br> False

xz_007 [3.2K]

Answer:

False

Step-by-step explanation:

a linear function is always in the form y=(f)x=bx+a

That means that there will not be one set answer and the line can be graphed. Your question is an equation, but not a linear one because there is only one set answer which would be 17/2=8.5.

5 0

2 years ago

How does the graph of g(x) = 2^x+3 differ from the graph of f(x) = 2^x ? **WILL BE GIVING BRAINLIEST**

Evgen [1.6K]

The graph of g(x) will be moved 3 units up i believe!!

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2 years ago

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Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

2 years ago